Double Dummy Corner

 

Competition Problem 168

composed by Stefan Ralescu
twin problems, presented for solving in
March 2019

                                    Problem A:

♠ A32

 Q985

 AQ32

♣ A4

♠ K1085

 2

 KJ987

♣ KJ9

♠ J6

 J1063

 6

♣ Q108765

♠ Q974

 AK74

 1054

♣ 32

West leads to Souths three hearts.  East-West to defeat the contract.

Successful solvers:  Nobody solved Problem A.  Mea culpa for choosing to present the two problems together.  Those who solved the second problem below failed to see the need for the precise defence required on the one above.  Better, perhaps, would have been to present the two problems in successive months, the defensive version first.

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Solution

Declarer has eight top tricks via red suit finesses and on a passive defence will come to a ninth by drawing trumps and applying endgame pressure on West.  West must therefore attack clubs, East then threatening to score club tricks should declarer draw trumps.  In fact West must lead the K, as East might be required to overtake both the 9 and the J if declarer opts to win the first trick.

A.      Suppose North wins the first trick with the A and leads the 5.  Then East must play the 6!  South wins with the 7 but note that it is now impossible to play two more rounds of trumps such that the remaining hearts in both North and South are higher than East’s.  Declarer might as well exit in clubs now, but East overtakes West’s card and returns a diamond to North’s Q.  East then covers North’s 9 and West discards a diamond.  We now have this position, with South on lead and defenders requiring four more tricks:

♠ A32

 Q8

 A32

♣ none

♠ K1085

 none

 KJ9

♣ J

♠ J6

 J3

 none

♣ Q876

♠ Q974

 A4

 105

♣ none

1.       If declarer now tries one more round of trumps, then West must discard the 5, regardless of whether the trick is taken in North or South.  Declarer can set up the long spade now but West gets in twice to attack diamonds, East refusing to ruff North’s A.  West gets in a second time in spades, cashes the J, and leads the good 9.  If South’s last heart is the 4, East ruffs with the J for the setting trick; otherwise East discards, South has to ruff with the top heart, and the J beats North’s 8 at trick thirteen.

2.       If instead declarer leads a spade to the A in the above position, East must drop the J.  North can now lead the 8 and run it if East plays low, thus making sure that both North and South can beat East’s last heart, but in fact it matters not which heart East plays on this trick.  West discards a diamond and now:

(i)      If the next lead is a spade, West wins as cheaply as possible and leads the J.  Declarer’s and dummy’s last trumps make separately but East can ruff the A and West still has a spade tenace over South.

(ii)      If it is a diamond, East ruffs the A and leads a spade.  West makes two spade tricks and a diamond.

B.      If North lets the K hold, West continues the suit.  Again East plays the 6 on North’s 5 and thereafter the play is as in line A except that South leads the first diamond instead of East.

Traps:

1.       If West starts with a lower club, declarer wins the first trick and can play two or three rounds of trumps before exiting in clubs.  If East wins the second club declarer will be able to draw trumps and throw West in on diamonds to get a favourable spade lead.  And if West plays the K the next lead is to declarer’s advantage one way or another.

2.       If East plays the 9 on the first heart, South wins, crosses to North on a diamond finesse, and leads the 8, followed by the 10 if the 8 holds.  Whatever East does, South’s and North’s last hearts will now both be higher than East’s and West is squeezed on the third heart: the club discard lets declarer draw trumps and throw West in, whereas a spade or diamond discard lets declarer establish a long card in the discarded suit.

                                    Problem B:

DR8

♠ A32

 K985

 AQ32

♣ A4

♠ K1085

 2

 KJ987

♣ KJ9

♠ J6

 J1063

 6

♣ Q108765

♠ Q974

 AQ74

 1054

♣ 32

South to make three hearts against any lead by West.

Successful solvers:  Zoran Sibinović, Rajeswar Tewari.

The tiny change in layout from that of 168a is of course intended to guide solvers towards the solutions to both problems.

West’s best lead is the K, which is allowed to hold.  North wins the club continuation, and leads the 5.  East does best to play the 6 but South wins with the 7, cashes the A and advances the Q in this position:

♠ A32

 K8

 AQ32

♣ none

♠ K1085

 none

 KJ98

♣ J

♠ J6

 J10

 6

♣ Q1087

♠ Q974

 Q4

 1054

♣ none

A.      If West discards the J, declarer can simply draw trumps and then has several ways of getting two favourable leads from West—e.g., exit on a low diamond, win the high diamond return and throw West back in for a spade lead.

B.      If West discards a diamond, North plays low, finesses the Q, and continues the suit.  East can score the J but the clubs are no longer a threat and declarer makes three more tricks and the contract with a ruff in each hand and North’s long diamond.

C.      If West discards the 5, North overtakes the Q!  A low spade from North puts West on lead, South covering the J if East plays that card.  West does best to exit in clubs but North ruffs and South discards a diamond.  The A and another spade now put West back on lead for a diamond lead into North’s tenace.  North captures the K (say) with the A and leads the Q.  East can make only the good J, South’s last two cards being the 4 and a spade winner.  (It makes no real difference if East discards a diamond on the third spade and ruffs the A.)

See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.

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© Hugh Darwen, 2019
Date last modified: 11 June, 2019