Competition Problem 156a
South to make one no-trump. West leads the ♦K.
Successful solvers: Steve Bloom, Ian Budden, Zoran Sibinović, Rajeswar Tewari, Wim van der Zijden
Winning the first trick with the ♦A, South immediately exits on a low club to Eastís ♣J. West wins the next trick with the ♦Q, South discarding the ♠2. West does best now to cash a top heart, on which North must drop an honour, South a middle card (!), then to switch to the ♣K. South lets this hold the trick and West continues the suit, bowing to the inevitable (but see below if West switches to hearts). South wins two club tricks and advances the remaining middle heart. West can do no better than win this trick and exit with the ♥6, but North plays the carefully preserved ♥8 and East is caught in a see-saw squeeze in this position:
A. If East comes down to one diamond, North retains the lead and either loses a diamond immediately or plays the ♠Q. In either case East can win only one trick.
B. If East instead comes down to two spades, South overtakes the ♥8 and loses the carefully preserved ♥3 to West, North discarding the ♠Q. Southís spades take the last three tricks.
If West plays the ♥K and another heart after winning the ♣K, North wins and leads the ♠Q, which holds. After the ♣A and ♥9, West is thrown in on the ♣Q to lead a spade into Southís ♠A-J tenace.
See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.
Hugh Darwen, 2018