Competition Problem 115b
by Ian Budden
South to make three no-trumps. West leads the ♠10.
Successful solvers: Jean-Marc Bihl, Steve Bloom, Wing-Kai Hon, Radu Mihai, Sebastian Nowacki, Wim van der Zijden Tables
Some proposed a lower DR but I was impressed by the fact that a few solvers went wrong on this one.
North wins the first trick with the ♠A, and leads the ♦Q, won by Westís ♦K. West switches to the ♥10. North and East play low. South wins with the ♥K, and leads a low spade to the ♠J.
A. East wins and plays:
1. the ♥A and the ♥J which runs to Northís ♥Q. Declarer can now play on straightforward lines, cashing the ♣A, finessing a diamond, and just giving up a club to West.
2. a spade to the ♠Q. South leads a low club to Northís ♣10 and Eastís ♣K. East exits with, say, a low diamond, but declarer can make two diamonds, the last spade, and three more clubs by leading a high club from South.
3. the ♣K. This is allowed to hold the trick. Play then reverts to line 2.
B. East ducks. North leads the ♣J to Eastís ♣K. To remove Southís entry before the long spade is established, East exits with the ♦J, won by Southís ♦A. South leads a high club, which holds the trick, and then takes a club finesse, cashes the ♦10 (and, optionally, the last club), and throws East in with a spade, forcing a lead to the ♥Q.
See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.
Hugh Darwen, 2014