Competition Problem 103a
South to make five clubs against any lead by West.
Successful solvers: Steve Bloom, Ian Budden, Leigh Matheson, Sebastian Nowacki, Radu Mihai, F.Y. Sing, Dick Yuen, Wim van der Zijden
Unless the ♠A is cashed at trick one the contract can be made by throwing West in on that card. For example, on a club lead, North wins and leads a low diamond to the ♦K. There follows a red suit cross-ruff for the next six tricks, including South’s ruff of the ♦A! The ♣A draws the remaining trumps and West is put in on a spade. West has a long diamond to cash but must then lead into South’s ♥J9 tenace.
So, West cashes the ♠A and switches to a club. Again North wins and leads a diamond to South’s ♦K. The first heart ruff follows but this time North cashes the ♦A, South throwing the club loser, to leave this, with North on lead:
Now comes the key play: North leads a spade (not a diamond) and South ruffs it with the ♣A. West is caught in a backwash squeeze without the count.
A. “Discarding” the ♣10 clearly makes life easy for declarer. The next four tricks are cross-ruffed and then the ♣9 draws East’s ♣8 and the ♥J is the eleventh trick.
B. Discarding a heart allows South to establish two heart tricks by ruffing one and drawing trumps. A low heart is then conceded to East and South is high with a trump and ♥J9.
C. Discarding a diamond allows declarer to cross-ruff the red suits for the next four tricks, then throw West in with the last trump for a heart lead into ♥J9.
See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.
© Hugh Darwen, 2013
Date last modified: 11 March, 2017