Competition Problem 58
by Luigi Caroli, Paolo Treossi, and Carlo
South to make three no-trumps when West leads (a) the ♣3, (b) the ♥2.
Successful solvers: Rajeswar Tewari, Wim van der Zijden
(a) When West leads the ♣3, South wins with the ♣J and advances the ♦Q, which is allowed to hold (best). Now comes the ♥K.
A. If West plays the ♥2, the ♥K wins. Next comes the ♠K, which also wins, East dropping the ♠9. This is followed by a diamond to West’s ♦K. West exits with a club to South’s ♣K (so the four kings have won four consecutive tricks!). South now leads the ♠Q.
1. If West wins and East plays low, then East will eventually be thrown in and forced to let North win two heart tricks.
2. If West ducks and East drops the ♠J, then South plays ♣A and another club and West is endplayed.
3. If West wins and East drops the ♠J, West tries the ♥Q but that is allowed to hold. Now South makes the ♣A and ♠10 and exits on a diamond so that North’s ♥A and long diamond take the last two tricks.
B. If West drops the ♥Q, North overtakes with the ♥A and cashes the ♥J, South discarding the ♠4. After a diamond to West’s ♦K declarer comes to nine tricks quite easily.
(b) When West leads the ♥2, South wins and this time advances the ♦10! When West ducks, North overtakes with the ♦J so that when East also ducks North can cash two heart tricks, South discarding clubs. West does best to discard a spade, but in that case South finesses the ♠10. Whether West wins or ducks, that player will eventually be thrown in to lead away from the ♣Q.
See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.
© Hugh Darwen, 2009
Date last modified: 15 April, 2017