Competition Problem 45
composed by Steve Bloom
presented for solving in November, 2008
South to make six diamonds. West leads the ♦10.
Successful solvers: Ian Budden, Abby Chiu, Tommy Cho, Bu Feiming, Leigh Matheson, Jim Munday, Gary Stevens, Rajeswar Tewari, Paolo Treossi, Pengcheng Wu, Dick Yuen, Wim van der Zijden.
North must win with the ♦K and East does best to drop the ♦8. North cashes the ♠K, plays a second diamond to South's ♦A, and ruffs a low spade.
A. If East still has the ♦Q, North cashes the ♣A and throws East in with a diamond. The heart return gives South two entries to set up and enjoy the spades.
B. If East has played the ♦Q, North wins the remaining trumps, South discarding two spades and a high club. West does best to keep four clubs and two spades. North leads the ♥Q, West discarding a club.
1. If West has kept the ♣KQJ, South wins a second heart to squeeze West without the count in the black suits.
2. If instead West has kept ♣KQ4, a club is conceded, South playing high. If East wins, the heart return to South squeezes West. If West overtakes East's ♣9, North will be able to finesse the ♣6.
Minor dual: In Line B, North can optionally lead the ♥Q at tricks 5 or 6 (or even trick 7, so long as South has not already discarded two spades).
Some solvers missed the possibility that West might keep the ♣4; others that East might keep the ♦3.
See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.
© Hugh Darwen, 2007
Date last modified: 03 June, 2019