Competition Problem 13
by Hugh Darwen
South to make four no-trumps. West leads the ♦7.
Successful solvers: Jean-Marc Bihl, Steve Bloom, Leigh Matheson, Dick Yuen, Wim van der Zijden
Very few solutions were submitted but I cannot believe it was that difficult. Is there enough interest to keep this feature going?
South overtakes the ♦9 with the ♦10 and leads a low spade, which West does best to win with the ♠K.
A. If West leads a diamond, North wins and advances the ♣J, which East covers. South wins with the ♣A and leads the ♦Q to pin the ♦J and establish the ♦6, North discarding a heart. East does best to win with the ♦K and lead a heart, covered all round. North advances the ♣9, taken by West, who returns a high heart to North. South comes to hand on the ♣10 and cashes the good diamond to subject West to an inverted squeeze in the major suits.
B. If West leads a spade, North wins with the ♠Q and can either play on clubs, in which case South sets up the ♦6 as before and play ends in a straightforward squeeze on West, or can simply give up a heart trick and eventually come to four hearts, three diamonds, the ♠Q and the black suit aces.
If East ducks the first club, West wins and returns a high heart, making the play similar to line A. Other defences, such as winning the first diamond or allowing North to win the first spade, all make the play easier for declarer.
See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.
© Hugh Darwen, 2006
Date last modified: 11 March, 2017