Double Dummy Corner

 

Competition Problem 8

composed by Hugh Darwen (after Julian Pottage)
presented for solving in October, 2005

DR3

♠ AK432

 Q2

 none

♣ QJ10987

♠ 6

 8765

 109654

♣ A65

♠ J10987

 J109

 AQ32

♣ K

♠ Q5

 AK43

 KJ87

♣ 432

West to lead and East-West to defeat South's three no-trumps.

Successful solvers:  Robin Adey, Bob Bignall, Jean-Marc Bihl, Steve Bloom, Clint Fyke, Andy Prothero, DaniŽl de Lind van Wijngaarden, Wim van der Zijden

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Solution

West must lead 10, which East must duck.  If South ducks too, West must follow with a low diamond to East's Q and South's K, in which case South gives up a club and East returns a low diamond to South's J.  If instead South wins the first trick with J and gives up a club to East's K, East must return Q, which South ducks, and follow with a low diamond to South's K.  In both cases we have had three rounds of diamonds, East retaining A, and one of clubs.  Now, if South leads:

A.      a club, West wins with A and East discards the A so that West can score two diamond tricks to defeat the contract.

B.      a diamond, East must return a heart, for a spade return would allow West to be squeezed, with or without the count, by three or four rounds of spades, South being able to discard a club on the thirdónote that North needs a heart entry for the squeeze to work and so does South.

C.      Q and another spade, North playing low, East must again return a heart, for much the same reason as in B.

If East had not deliberately blocked the diamonds by hanging on to the A, declarer would have been able to squeeze West by playing three rounds of spades.  A club can be discarded on the second, but on the third West must either give the ninth trick immediately by unguarding hearts (or clubs), or must discard a diamond winner, allowing the ninth trick to be established in clubs.

See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.

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© Hugh Darwen, 2014

Date last modified: 05 May, 2017